原始矩阵（直接影响矩阵）为

$$Ori=\begin{array}{|c|c|c|c|c|c|c|}\hline {M_{12 \times12}} &H1 &H2 &H3 &K1 &K2 &K3 &X1 &X2 &X3 &S1 &S2 &S3\\ \hline H1 &0 &2 &1 &0 &9 &0 &2 &9 &1 &0 &2 &1\\ \hline H2 &3 &0 &0 &0 &9 &8 &0 &7 &0 &3 &2 &1\\ \hline H3 &3 &9 &0 &3 &0 &0 &3 &0 &0 &0 &2 &6\\ \hline K1 &3 &9 &4 &0 &0 &0 &1 &5 &0 &0 &2 &5\\ \hline K2 &6 &9 &0 &0 &0 &0 &0 &0 &5 &0 &2 &1\\ \hline K3 &8 &5 &2 &0 &1 &0 &2 &0 &9 &0 &2 &1\\ \hline X1 &3 &0 &0 &0 &0 &0 &0 &0 &9 &0 &2 &1\\ \hline X2 &0 &6 &2 &5 &0 &4 &1 &0 &0 &2 &2 &1\\ \hline X3 &9 &0 &0 &0 &0 &8 &7 &8 &8 &0 &2 &1\\ \hline S1 &0 &0 &3 &3 &3 &5 &8 &8 &8 &0 &0 &1\\ \hline S2 &0 &3 &0 &0 &0 &8 &4 &8 &8 &0 &0 &1\\ \hline S3 &5 &0 &0 &4 &5 &8 &8 &8 &8 &0 &2 &0\\ \hline \end{array} $$

规范直接关系矩阵求解过程 $$ \require{cancel} \require{AMScd} \begin{CD} O @>>>N \\ \end{CD} $$

$$\mathcal{N}=\begin{array}{|c|c|c|c|c|c|c|}\hline {M_{12 \times12}} &H1 &H2 &H3 &K1 &K2 &K3 &X1 &X2 &X3 &S1 &S2 &S3\\ \hline H1 &0 &0.028 &0.014 &0 &0.126 &0 &0.028 &0.126 &0.014 &0 &0.028 &0.014\\ \hline H2 &0.042 &0 &0 &0 &0.126 &0.112 &0 &0.098 &0 &0.042 &0.028 &0.014\\ \hline H3 &0.042 &0.126 &0 &0.042 &0 &0 &0.042 &0 &0 &0 &0.028 &0.084\\ \hline K1 &0.042 &0.126 &0.056 &0 &0 &0 &0.014 &0.07 &0 &0 &0.028 &0.07\\ \hline K2 &0.084 &0.126 &0 &0 &0 &0 &0 &0 &0.07 &0 &0.028 &0.014\\ \hline K3 &0.112 &0.07 &0.028 &0 &0.014 &0 &0.028 &0 &0.126 &0 &0.028 &0.014\\ \hline X1 &0.042 &0 &0 &0 &0 &0 &0 &0 &0.126 &0 &0.028 &0.014\\ \hline X2 &0 &0.084 &0.028 &0.07 &0 &0.056 &0.014 &0 &0 &0.028 &0.028 &0.014\\ \hline X3 &0.126 &0 &0 &0 &0 &0.112 &0.098 &0.112 &0 &0 &0.028 &0.014\\ \hline S1 &0 &0 &0.042 &0.042 &0.042 &0.07 &0.112 &0.112 &0.112 &0 &0 &0.014\\ \hline S2 &0 &0.042 &0 &0 &0 &0.112 &0.056 &0.112 &0.112 &0 &0 &0.014\\ \hline S3 &0.07 &0 &0 &0.056 &0.07 &0.112 &0.112 &0.112 &0.112 &0 &0.028 &0\\ \hline \end{array} $$

综合影响矩阵求解过程 $$\begin{CD} N @>>>T \\ \end{CD} $$

　　综合影响矩阵如下

$T=\mathcal{N}(I-\mathcal{N})^{-1}$

$$T=\begin{array}{|c|c|c|c|c|c|c|}\hline {M_{12 \times12}} &H1 &H2 &H3 &K1 &K2 &K3 &X1 &X2 &X3 &S1 &S2 &S3\\ \hline H1 &0.028 &0.067 &0.02 &0.013 &0.14 &0.029 &0.043 &0.15 &0.042 &0.007 &0.044 &0.024\\ \hline H2 &0.082 &0.047 &0.012 &0.013 &0.148 &0.141 &0.024 &0.132 &0.046 &0.048 &0.047 &0.026\\ \hline H3 &0.071 &0.148 &0.007 &0.051 &0.035 &0.039 &0.064 &0.047 &0.033 &0.008 &0.044 &0.095\\ \hline K1 &0.071 &0.157 &0.063 &0.016 &0.035 &0.042 &0.037 &0.114 &0.029 &0.01 &0.046 &0.084\\ \hline K2 &0.111 &0.143 &0.004 &0.005 &0.034 &0.036 &0.019 &0.046 &0.089 &0.007 &0.042 &0.022\\ \hline K3 &0.149 &0.094 &0.033 &0.007 &0.047 &0.039 &0.057 &0.054 &0.152 &0.005 &0.046 &0.026\\ \hline X1 &0.066 &0.01 &0.003 &0.003 &0.011 &0.025 &0.021 &0.032 &0.14 &0.001 &0.037 &0.019\\ \hline X2 &0.028 &0.112 &0.037 &0.077 &0.022 &0.084 &0.032 &0.035 &0.028 &0.034 &0.041 &0.028\\ \hline X3 &0.159 &0.035 &0.011 &0.013 &0.028 &0.138 &0.12 &0.15 &0.046 &0.006 &0.048 &0.026\\ \hline S1 &0.051 &0.044 &0.053 &0.057 &0.058 &0.107 &0.142 &0.151 &0.155 &0.006 &0.024 &0.033\\ \hline S2 &0.046 &0.072 &0.01 &0.013 &0.019 &0.151 &0.084 &0.148 &0.149 &0.007 &0.02 &0.025\\ \hline S3 &0.13 &0.054 &0.015 &0.07 &0.097 &0.155 &0.146 &0.166 &0.168 &0.007 &0.057 &0.02\\ \hline \end{array} $$

由综合影响矩阵求影响度、被影响度、中心度、原因度 \begin{CD} T @>>>\{D|C|M|R \} \\ \end{CD}

　　影响度、被影响度、中心度与原因度是四种度量要素在系统里影响程度的度量值。都是根据综合影响矩阵计算得出。

求解原理

影响度 $D$	$$ D_i=\sum \limits_{j=1}^{n}{t_{ij}},(i=1,2,3,\cdots,n) $$
被影响度 $C$	$$ C_i=\sum \limits_{j=1}^{n}{t_{ji}},(i=1,2,3,\cdots,n) $$
中心度 $M$	$$ M_i=D_i+C_i $$
原因度 $ R$	$$ R_i=D_i-C_i $$

结果

影响度、被影响度、中心度、原因度

$$\begin{array}{|c|c|c|c|c|c|c|}\hline {M_{12 \times4}} &Di &Ci &Mi &Ri\\ \hline H1 &0.606 &0.992 &1.597 &-0.386\\ \hline H2 &0.765 &0.983 &1.748 &-0.219\\ \hline H3 &0.642 &0.269 &0.911 &0.374\\ \hline K1 &0.704 &0.337 &1.041 &0.367\\ \hline K2 &0.559 &0.676 &1.235 &-0.117\\ \hline K3 &0.711 &0.986 &1.697 &-0.275\\ \hline X1 &0.369 &0.789 &1.159 &-0.42\\ \hline X2 &0.559 &1.226 &1.785 &-0.667\\ \hline X3 &0.78 &1.076 &1.856 &-0.296\\ \hline S1 &0.881 &0.145 &1.027 &0.736\\ \hline S2 &0.745 &0.497 &1.242 &0.248\\ \hline S3 &1.084 &0.429 &1.512 &0.655\\ \hline \end{array} $$

绘制中心度与原因度建构的散点图图表

从两列的决策矩阵到关系矩阵

$$ \begin{CD} D=\left[ d_{ij} \right]_{n \times 2}@>取偏序>>A=\left[a_{ij} \right]_{n \times n} \\ \end{CD} $$

中心度，原因度绝对值组成的决策矩阵D

$$D=\begin{array}{c|c|c|c|c|c|c}{M_{12 \times2}} &M &|R|\\ \hline H1 &1.5974 &0.3857\\ \hline H2 &1.7475 &0.2185\\ \hline H3 &0.9105 &0.3735\\ \hline K1 &1.0408 &0.3671\\ \hline K2 &1.2352 &0.1168\\ \hline K3 &1.6971 &0.275\\ \hline X1 &1.1586 &0.4199\\ \hline X2 &1.7845 &0.6674\\ \hline X3 &1.8556 &0.2958\\ \hline S1 &1.0268 &0.7358\\ \hline S2 &1.2415 &0.2479\\ \hline S3 &1.5124 &0.6547\\ \hline \end{array} $$

关系矩阵$A$

$$A=\begin{array} {c|c|c|c|c|c|c|c}{M_{12 \times12}} &H1 &H2 &H3 &K1 &K2 &K3 &X1 &X2 &X3 &S1 &S2 &S3\\ \hline H1 &1 & & & & & & &1 & & & & \\ \hline H2 & &1 & & & & & &1 &1 & & & \\ \hline H3 &1 & &1 & & & &1 &1 & &1 & &1\\ \hline K1 &1 & & &1 & & &1 &1 & & & &1\\ \hline K2 &1 &1 & & &1 &1 & &1 &1 & &1 &1\\ \hline K3 & & & & & &1 & &1 &1 & & & \\ \hline X1 & & & & & & &1 &1 & & & &1\\ \hline X2 & & & & & & & &1 & & & & \\ \hline X3 & & & & & & & & &1 & & & \\ \hline S1 & & & & & & & & & &1 & & \\ \hline S2 &1 & & & & &1 & &1 &1 & &1 &1\\ \hline S3 & & & & & & & &1 & & & &1\\ \hline \end{array} $$

AISM部分求解

关系矩阵到相乘矩阵

\begin{CD} A@>A+I>>B \\ \end{CD}

$$B=\begin{array} {c|c|c|c|c|c|c|c}{M_{12 \times12}} &H1 &H2 &H3 &K1 &K2 &K3 &X1 &X2 &X3 &S1 &S2 &S3\\ \hline H1 &1 & & & & & & &1 & & & & \\ \hline H2 & &1 & & & & & &1 &1 & & & \\ \hline H3 &1 & &1 & & & &1 &1 & &1 & &1\\ \hline K1 &1 & & &1 & & &1 &1 & & & &1\\ \hline K2 &1 &1 & & &1 &1 & &1 &1 & &1 &1\\ \hline K3 & & & & & &1 & &1 &1 & & & \\ \hline X1 & & & & & & &1 &1 & & & &1\\ \hline X2 & & & & & & & &1 & & & & \\ \hline X3 & & & & & & & & &1 & & & \\ \hline S1 & & & & & & & & & &1 & & \\ \hline S2 &1 & & & & &1 & &1 &1 & &1 &1\\ \hline S3 & & & & & & & &1 & & & &1\\ \hline \end{array} $$

相乘矩阵B到可达矩阵R

\begin{CD} B@>连乘或者幂乘>>R \\ \end{CD}

可达矩阵R

$$R=\begin{array} {c|c|c|c|c|c|c|c}{M_{12 \times12}} &H1 &H2 &H3 &K1 &K2 &K3 &X1 &X2 &X3 &S1 &S2 &S3\\ \hline H1 &1 & & & & & & &1 & & & & \\ \hline H2 & &1 & & & & & &1 &1 & & & \\ \hline H3 &1 & &1 & & & &1 &1 & &1 & &1\\ \hline K1 &1 & & &1 & & &1 &1 & & & &1\\ \hline K2 &1 &1 & & &1 &1 & &1 &1 & &1 &1\\ \hline K3 & & & & & &1 & &1 &1 & & & \\ \hline X1 & & & & & & &1 &1 & & & &1\\ \hline X2 & & & & & & & &1 & & & & \\ \hline X3 & & & & & & & & &1 & & & \\ \hline S1 & & & & & & & & & &1 & & \\ \hline S2 &1 & & & & &1 & &1 &1 & &1 &1\\ \hline S3 & & & & & & & &1 & & & &1\\ \hline \end{array} $$

由可达矩阵通过对抗的抽取方式得到一对要素的层级分布 \begin{CD} R @>结果优先抽取>原因优先抽取> \frac {up型要素层级分布 }{down 型要素层级分布} \\ \end{CD}

可达矩阵R层级抽取的过程如下

结果优先——UP型抽取过程	原因优先——DOWN型抽取过程
$$\begin{array} {c\|c\|c\|c\|c\|c\|c\|c}{} & R_{e} & T_{e} \\\hline H1&H1,X2&H1 \\\hline H2&H2,X2,X3&H2 \\\hline H3&H1,H3,X1,X2,S1,S3&H3 \\\hline K1&H1,K1,X1,X2,S3&K1 \\\hline K2&H1,H2,K2,K3,X2,X3,S2,S3&K2 \\\hline K3&K3,X2,X3&K3 \\\hline X1&X1,X2,S3&X1 \\\hline X2&\color{red}{\fbox{X2}}&\color{red}{\fbox{X2}} \\\hline X3&\color{red}{\fbox{X3}}&\color{red}{\fbox{X3}} \\\hline S1&\color{red}{\fbox{S1}}&\color{red}{\fbox{S1}} \\\hline S2&H1,K3,X2,X3,S2,S3&S2 \\\hline S3&X2,S3&S3 \\\hline \end{array} $$	$$\begin{array} {c\|c\|c\|c\|c\|c\|c\|c}{} &Q_{e} & T_{e} \\\hline H1&H1,H3,K1,K2,S2&H1 \\\hline H2&H2,K2&H2 \\\hline H3&\color{blue}{\fbox{H3}}&\color{blue}{\fbox{H3}} \\\hline K1&\color{blue}{\fbox{K1}}&\color{blue}{\fbox{K1}} \\\hline K2&\color{blue}{\fbox{K2}}&\color{blue}{\fbox{K2}} \\\hline K3&K2,K3,S2&K3 \\\hline X1&H3,K1,X1&X1 \\\hline X2&H1,H2,H3,K1,K2,K3,X1,X2,S2,S3&X2 \\\hline X3&H2,K2,K3,X3,S2&X3 \\\hline S1&H3,S1&S1 \\\hline S2&K2,S2&S2 \\\hline S3&H3,K1,K2,X1,S2,S3&S3 \\\hline \end{array} $$
抽取出X2、X3、S1放置上层，删除后剩余的情况如下	抽取出H3,K1,K2放置下层，删除后剩余的情况如下
$$\begin{array} {c\|c\|c\|c\|c\|c\|c\|c}{} & R_{e} & T_{e} \\\hline H1&\color{red}{\fbox{H1}}&\color{red}{\fbox{H1}} \\\hline H2&\color{red}{\fbox{H2}}&\color{red}{\fbox{H2}} \\\hline H3&H1,H3,X1,S3&H3 \\\hline K1&H1,K1,X1,S3&K1 \\\hline K2&H1,H2,K2,K3,S2,S3&K2 \\\hline K3&\color{red}{\fbox{K3}}&\color{red}{\fbox{K3}} \\\hline X1&X1,S3&X1 \\\hline S2&H1,K3,S2,S3&S2 \\\hline S3&\color{red}{\fbox{S3}}&\color{red}{\fbox{S3}} \\\hline \end{array} $$	$$\begin{array} {c\|c\|c\|c\|c\|c\|c\|c}{} &Q_{e} & T_{e} \\\hline H1&H1,S2&H1 \\\hline H2&\color{blue}{\fbox{H2}}&\color{blue}{\fbox{H2}} \\\hline K3&K3,S2&K3 \\\hline X1&\color{blue}{\fbox{X1}}&\color{blue}{\fbox{X1}} \\\hline X2&H1,H2,K3,X1,X2,S2,S3&X2 \\\hline X3&H2,K3,X3,S2&X3 \\\hline S1&\color{blue}{\fbox{S1}}&\color{blue}{\fbox{S1}} \\\hline S2&\color{blue}{\fbox{S2}}&\color{blue}{\fbox{S2}} \\\hline S3&X1,S2,S3&S3 \\\hline \end{array} $$
抽取出H1、H2、K3、S3放置上层，删除后剩余的情况如下	抽取出H2,X1,S1,S2放置下层，删除后剩余的情况如下
$$\begin{array} {c\|c\|c\|c\|c\|c\|c\|c}{} & R_{e} & T_{e} \\\hline H3&H3,X1&H3 \\\hline K1&K1,X1&K1 \\\hline K2&K2,S2&K2 \\\hline X1&\color{red}{\fbox{X1}}&\color{red}{\fbox{X1}} \\\hline S2&\color{red}{\fbox{S2}}&\color{red}{\fbox{S2}} \\\hline \end{array} $$	$$\begin{array} {c\|c\|c\|c\|c\|c\|c\|c}{} &Q_{e} & T_{e} \\\hline H1&\color{blue}{\fbox{H1}}&\color{blue}{\fbox{H1}} \\\hline K3&\color{blue}{\fbox{K3}}&\color{blue}{\fbox{K3}} \\\hline X2&H1,K3,X2,S3&X2 \\\hline X3&K3,X3&X3 \\\hline S3&\color{blue}{\fbox{S3}}&\color{blue}{\fbox{S3}} \\\hline \end{array} $$
抽取出X1、S2放置上层，删除后剩余的情况如下	抽取出H1,K3,S3放置下层，删除后剩余的情况如下
$$\begin{array} {c\|c\|c\|c\|c\|c\|c\|c}{} & R_{e} & T_{e} \\\hline H3&\color{red}{\fbox{H3}}&\color{red}{\fbox{H3}} \\\hline K1&\color{red}{\fbox{K1}}&\color{red}{\fbox{K1}} \\\hline K2&\color{red}{\fbox{K2}}&\color{red}{\fbox{K2}} \\\hline \end{array} $$	$$\begin{array} {c\|c\|c\|c\|c\|c\|c\|c}{} &Q_{e} & T_{e} \\\hline X2&\color{blue}{\fbox{X2}}&\color{blue}{\fbox{X2}} \\\hline X3&\color{blue}{\fbox{X3}}&\color{blue}{\fbox{X3}} \\\hline \end{array} $$
抽取出H3、K1、K2放置上层，删除后剩余的情况如下	抽取出X2,X3放置下层，删除后剩余的情况如下

抽取方式的结果如下

层级	结果优先——UP型	原因优先——DOWN型
第0层	X2,X3,S1	X2,X3
第1层	H1,H2,K3,S3	H1,K3,S3
第2层	X1,S2	H2,X1,S1,S2
第3层	H3,K1,K2	H3,K1,K2

计算一般性骨架矩阵 \begin{CD} R @>缩点运算>>R' @>缩边运算>>S' @>以最简菊花链表示回路>>S \\ \end{CD}

一般性骨架矩阵即为不缩点的情况下的最简结构，即边数最少。$S$如下

$$S=\begin{array} {c|c|c|c|c|c|c|c}{M_{12 \times12}} &H1 &H2 &H3 &K1 &K2 &K3 &X1 &X2 &X3 &S1 &S2 &S3\\ \hline H1 & & & & & & & &1 & & & & \\ \hline H2 & & & & & & & &1 &1 & & & \\ \hline H3 &1 & & & & & &1 & & &1 & & \\ \hline K1 &1 & & & & & &1 & & & & & \\ \hline K2 & &1 & & & & & & & & &1 & \\ \hline K3 & & & & & & & &1 &1 & & & \\ \hline X1 & & & & & & & & & & & &1\\ \hline X2 & & & & & & & & & & & & \\ \hline X3 & & & & & & & & & & & & \\ \hline S1 & & & & & & & & & & & & \\ \hline S2 &1 & & & & &1 & & & & & &1\\ \hline S3 & & & & & & & &1 & & & & \\ \hline \end{array} $$

代入一般性骨架矩阵$S$，绘制对抗层级拓扑图

UP型

DOWN型

权重系列求解

$$ \begin{CD} \{M|R \}@>>> d @>>>\omega \\ \end{CD} $$

　　$ \{M|R \}$ 为要素的中心度与原因度

　　$d$　两者合成距离向量

　　$ \omega $ 权重

求解原理

$$d = \sqrt {M^2 + R^2} $$

$$MR=\begin{array}{c|c|c|c|c|c|c}{M_{12 \times2}} &中心度 &原因度\\ \hline H1 &1.5974 &0.3857\\ \hline H2 &1.7475 &0.2185\\ \hline H3 &0.9105 &0.3735\\ \hline K1 &1.0408 &0.3671\\ \hline K2 &1.2352 &0.1168\\ \hline K3 &1.6971 &0.275\\ \hline X1 &1.1586 &0.4199\\ \hline X2 &1.7845 &0.6674\\ \hline X3 &1.8556 &0.2958\\ \hline S1 &1.0268 &0.7358\\ \hline S2 &1.2415 &0.2479\\ \hline S3 &1.5124 &0.6547\\ \hline \end{array} $$

向量的计算采用欧式距离公式

$$d=\begin{array}{c|c|c|c|c|c|c}{M_{12 \times1}} &向量\\ \hline H1 &1.6433\\ \hline H2 &1.7611\\ \hline H3 &0.9842\\ \hline K1 &1.1036\\ \hline K2 &1.2408\\ \hline K3 &1.7192\\ \hline X1 &1.2323\\ \hline X2 &1.9053\\ \hline X3 &1.879\\ \hline S1 &1.2632\\ \hline S2 &1.266\\ \hline S3 &1.6481\\ \hline \end{array} $$

归一化求权重

$$\omega =\begin{array}{c|c|c|c|c|c|c}{M_{12 \times1}} &权重\\ \hline H1 &0.0931\\ \hline H2 &0.0998\\ \hline H3 &0.0558\\ \hline K1 &0.0625\\ \hline K2 &0.0703\\ \hline K3 &0.0974\\ \hline X1 &0.0698\\ \hline X2 &0.108\\ \hline X3 &0.1065\\ \hline S1 &0.0716\\ \hline S2 &0.0717\\ \hline S3 &0.0934\\ \hline \end{array} $$

归一化求子系统的权重

$$\omega =\begin{array}{c|c|c|c|c|c|c}{M_{4 \times1}} &权重\\ \hline H &0.2487\\ \hline K &0.2303\\ \hline X &0.2843\\ \hline S &0.2367\\ \hline \end{array} $$

DEMATEL-AISM-Weight

原始矩阵（直接影响矩阵）为

规范直接关系矩阵求解过程 $$ \require{cancel} \require{AMScd} \begin{CD} O @>>>N \\ \end{CD} $$

综合影响矩阵求解过程 $$\begin{CD} N @>>>T \\ \end{CD} $$

由综合影响矩阵求影响度、被影响度、中心度、原因度 \begin{CD} T @>>>\{D|C|M|R \} \\ \end{CD}

求解原理

结果

绘制中心度与原因度建构的散点图图表

从两列的决策矩阵到关系矩阵

AISM部分求解

关系矩阵到相乘矩阵

相乘矩阵B到可达矩阵R

由可达矩阵通过对抗的抽取方式得到一对要素的层级分布 \begin{CD} R @>结果优先抽取>原因优先抽取> \frac {up型要素层级分布 }{down 型要素层级分布} \\ \end{CD}

抽取方式的结果如下

计算一般性骨架矩阵 \begin{CD} R @>缩点运算>>R' @>缩边运算>>S' @>以最简菊花链表示回路>>S \\ \end{CD}

代入一般性骨架矩阵$S$，绘制对抗层级拓扑图

UP型

DOWN型

权重系列求解

求解原理

DEMATEL-AHDT流程图如下：