解释结构模型快速排序层级分析
此处输入要素的个数：
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甲 | 乙 | 丙 | 丁 | 戊 | 己 | 庚 | 辛 | 壬 | 癸 | 乾 | 坤 | 震 | 巽 | 坎 | 离 | 艮 | 兑 | 子 | 丑 |
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第一步：生成自乘矩阵
系统的邻接矩阵的表示
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甲 | 乙 | 丙 | 丁 | 戊 | 己 | 庚 | 辛 | 壬 | 癸 | 乾 | 坤 | 震 | 巽 | 坎 | 离 | 艮 | 兑 | 子 | 丑 |
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第二步：对系统进行环路分析，并获得一个获得一个新序
0=>甲
1=>壬
2=>乙+己+震
3=>丙
4=>坤
5=>坎
6=>子
7=>丁+乾
8=>艮
9=>戊
10=>庚
11=>辛
12=>癸
13=>巽
14=>离
15=>兑
16=>丑
第三步：根据环路与新序，进行矩阵缩减
分析的矩阵为：
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甲 | 壬 | 乙＋己＋震 | 丙 | 坤 | 坎 | 子 | 丁＋乾 | 艮 | 戊 | 庚 | 辛 | 癸 | 巽 | 离 | 兑 | 丑 |
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| 乙＋己＋震 |
壬、乙＋己＋震、 |
| 丙 |
壬、 |
| 坤 |
乙＋己＋震、 |
| 坎 |
乙＋己＋震、 |
| 子 |
坤、坎、 |
| 丁＋乾 |
子、丁＋乾、 |
| 戊 |
艮、 |
| 庚 |
乙＋己＋震、丙、坎、 |
| 辛 |
壬、 |
| 癸 |
艮、 |
| 巽 |
坎、 |
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第四步：对无环矩阵进行缩边，也就是去掉所有的向前边！
可达矩阵：
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甲 | 壬 | 乙＋己＋震 | 丙 | 坤 | 坎 | 子 | 丁＋乾 | 艮 | 戊 | 庚 | 辛 | 癸 | 巽 | 离 | 兑 | 丑 |
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骨架矩阵
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| 乙＋己＋震 |
壬、 |
| 丙 |
壬、 |
| 坤 |
乙＋己＋震、 |
| 坎 |
乙＋己＋震、 |
| 子 |
坤、坎、 |
| 丁＋乾 |
子、 |
| 戊 |
艮、 |
| 庚 |
丙、坎、 |
| 辛 |
壬、 |
| 癸 |
艮、 |
| 巽 |
坎、 |
| 离 |
坤、 |
第五步：对一般性骨架矩阵进行层级分解，可以是原因优先，可以是结果优先
原因优先层级划分最终图形
结果优先层级划分最终图形
弹性势能最大，两端发散的的层级结果
弹性势能最小，中间靠拢的结果
第六步：对一般性骨架矩阵的中的活动要素进行分析
| 层级的序号 | 原因优先的方法-得到的各层级的要素 | 结果优先的方法-得到的各层级要素 | 共同有的要素 | 活动的要素 |
| 1 | 壬 | 甲,壬,艮,兑,丑 | 壬 | 甲,艮,兑,丑 |
| 2 | 乙＋己＋震 | 乙＋己＋震,丙,戊,辛,癸 | 乙＋己＋震 | 丙,戊,辛,癸 |
| 3 | 坤,坎 | 坤,坎 | 坤,坎 | |
| 4 | 丙,子,艮 | 子,庚,巽,离 | 子 | 丙,艮,庚,巽,离 |
| 5 | 甲,丁＋乾,戊,庚,辛,癸,巽,离,兑,丑 | 丁＋乾 | 丁＋乾 | 甲,戊,庚,辛,癸,巽,离,兑,丑 |
由上表计算得出活动的要素以及它们活动的层级：
| 要素的序号 | 要素的名称 | 要素的标题 | 开始层级 | 终止层级 |
| 0 | 甲 | 甲 | 1 | 5 |
| 8 | 艮 | 艮 | 1 | 4 |
| 15 | 兑 | 兑 | 1 | 5 |
| 16 | 丑 | 丑 | 1 | 5 |
| 3 | 丙 | 丙 | 2 | 4 |
| 9 | 戊 | 戊 | 2 | 5 |
| 11 | 辛 | 辛 | 2 | 5 |
| 12 | 癸 | 癸 | 2 | 5 |
| 10 | 庚 | 庚 | 4 | 5 |
| 13 | 巽 | 巽 | 4 | 5 |
| 14 | 离 | 离 | 4 | 5 |
找到活动要素，并在层级中移动这些活动要素找出最好的结果。活动的要素要注意本身有因果关系的
A、分层的结果一定要符合箭头一定向上
B、不能增加层级的数目
这个方法很土鳖的，赶紧输入原始矩阵，赶紧看，3秒钟后跳转到更好的方法的页面！
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